# Conventions ## States and Bases ### Bases A basis refers to a set of two eigenstates. The transition between these two states is said to be addressed by a channel that targets that basis. Namely: ```{eval-rst} .. list-table:: :align: center :widths: 50 35 35 :header-rows: 1 * - Basis - Eigenstates - ``Channel`` type * - ``ground-rydberg`` - :math:`|g\rangle,~|r\rangle` - ``Rydberg`` * - ``digital`` - :math:`|g\rangle,~|h\rangle` - ``Raman`` * - ``XY`` - :math:`|0\rangle,~|1\rangle` - ``Microwave`` ``` ### Qutrit state The qutrit state combines the basis states of the `ground-rydberg` and `digital` bases, which share the same ground state, $|g\rangle$. This qutrit state comes into play in the digital approach, where the qubit state is encoded in $|g\rangle$ and $|h\rangle$ but then the Rydberg state $|r\rangle$ is accessed in multi-qubit gates. The qutrit state's basis vectors are defined as: $$ |r\rangle = (1, 0, 0)^T,~~|g\rangle = (0, 1, 0)^T, ~~|h\rangle = (0, 0, 1)^T. $$ ### Qubit states :::{caution} There is no implicit relationship between a state's vector representation and its associated measurement value. To see the measurement value of a state for each measurement basis, see {ref}`spam-table` . ::: When using only the `ground-rydberg` or `digital` basis, the qutrit state is not needed and is thus reduced to a qubit state. This reduction is made simply by tracing-out the extra basis state, so we obtain - `ground-rydberg`: $|r\rangle = (1, 0)^T,~~|g\rangle = (0, 1)^T$ - `digital`: $|g\rangle = (1, 0)^T,~~|h\rangle = (0, 1)^T$ On the other hand, the `XY` basis uses an independent set of qubit states that are labelled $|0\rangle$ and $|1\rangle$ and follow the standard convention: - `XY`: $|0\rangle = (1, 0)^T,~~|1\rangle = (0, 1)^T$ ### Multi-partite states The combined quantum state of multiple atoms respects their order in the `Register`. For a register with ordered atoms `(q0, q1, q2, ..., qn)`, the full quantum state will be $$ |q_0, q_1, q_2, ...\rangle = |q_0\rangle \otimes |q_1\rangle \otimes |q_2\rangle \otimes ... \otimes |q_n\rangle $$ :::{note} The atoms may be labelled arbitrarily without any inherent order, it's only the order with which they are stored in the `Register` (as returned by `Register.qubit_ids`) that matters . ::: ## State Preparation and Measurement ```{eval-rst} .. list-table:: Initial State and Measurement Conventions :name: spam-table :align: center :widths: 60 40 75 :header-rows: 1 * - Basis - Initial state - Measurement * - ``ground-rydberg`` - :math:`|g\rangle` - | | :math:`|r\rangle \rightarrow 1` | :math:`|g\rangle,|h\rangle \rightarrow 0` * - ``digital`` - :math:`|g\rangle` - | | :math:`|h\rangle \rightarrow 1` | :math:`|g\rangle,|r\rangle \rightarrow 0` * - ``XY`` - :math:`|0\rangle` - | | :math:`|1\rangle \rightarrow 1` | :math:`|0\rangle \rightarrow 0` ``` ### Measurement samples order Measurement samples are returned as a sequence of 0s and 1s, in the same order as the atoms in the `Register` and in the multi-partite state. For example, a four-qutrit state $|q_0, q_1, q_2, q_3\rangle$ that's projected onto $|g, r, h, r\rangle$ when measured will record a count to sample - `0101`, if measured in the `ground-rydberg` basis - `0010`, if measured in the `digital` basis ## Hamiltonians :::{tip} This section uses formulas that rely on the [Indexed Operator](#indexed-operator) notation. ::: Independently of the mode of operation, the Hamiltonian describing the system can be written as $$ H(t) = \sum_i \left (H^D_i(t) + \sum_{j